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9x^2-10x=9x^-6
We move all terms to the left:
9x^2-10x-(9x^-6)=0
We get rid of parentheses
9x^2-10x-9x^+6=0
We add all the numbers together, and all the variables
9x^2-19x+6=0
a = 9; b = -19; c = +6;
Δ = b2-4ac
Δ = -192-4·9·6
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{145}}{2*9}=\frac{19-\sqrt{145}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{145}}{2*9}=\frac{19+\sqrt{145}}{18} $
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